2x^2-2000=0

Solution for 2x^2-2000=0 equation:

2x^2-2000=0

a = 2; b = 0; c = -2000;
Δ = b2-4ac
Δ = 02-4·2·(-2000)
Δ = 16000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16000}=\sqrt{1600*10}=\sqrt{1600}*\sqrt{10}=40\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{10}}{2*2}=\frac{0-40\sqrt{10}}{4}
=-\frac{40\sqrt{10}}{4}
=-10\sqrt{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{10}}{2*2}=\frac{0+40\sqrt{10}}{4}
=\frac{40\sqrt{10}}{4}
=10\sqrt{10}
$